2011-12-12 06:15:18 +08:00
|
|
|
// The contents of this file are in the public domain. See LICENSE_FOR_EXAMPLE_PROGRAMS.txt
|
|
|
|
/*
|
|
|
|
|
|
|
|
This is an example illustrating the use of the dlib machine learning tools for
|
|
|
|
learning to solve the assignment problem.
|
|
|
|
|
|
|
|
Many tasks in computer vision or natural language processing can be thought of
|
|
|
|
as assignment problems. For example, in a computer vision application where
|
|
|
|
you are trying to track objects moving around in video, you likely need to solve
|
|
|
|
an association problem every time you get a new video frame. That is, each new
|
|
|
|
frame will contain objects (e.g. people, cars, etc.) and you will want to
|
|
|
|
determine which of these objects are actually things you have seen in previous
|
|
|
|
frames.
|
|
|
|
|
|
|
|
The assignment problem can be optimally solved using the well known Hungarian
|
|
|
|
algorithm. However, this algorithm requires the user to supply some function
|
2011-12-12 12:36:15 +08:00
|
|
|
which measures the "goodness" of an individual association. In many cases the
|
2011-12-12 06:15:18 +08:00
|
|
|
best way to measure this goodness isn't obvious and therefore machine learning
|
|
|
|
methods are used.
|
|
|
|
|
|
|
|
The remainder of this example program will show you how to learn a goodness
|
|
|
|
function which is optimal, in a certain sense, for use with the Hungarian
|
|
|
|
algorithm. To do this, we will make a simple dataset of example associations
|
|
|
|
and use them to train a supervised machine learning method.
|
|
|
|
*/
|
|
|
|
|
|
|
|
|
|
|
|
#include <iostream>
|
|
|
|
#include "dlib/svm_threaded.h"
|
|
|
|
|
|
|
|
using namespace std;
|
|
|
|
using namespace dlib;
|
|
|
|
|
|
|
|
|
|
|
|
// ----------------------------------------------------------------------------------------
|
|
|
|
|
|
|
|
/*
|
|
|
|
In an association problem, we will talk about the "Left Hand Set" (LHS) and the
|
|
|
|
"Right Hand Set" (RHS). The task will be to learn to map all elements of LHS to
|
|
|
|
unique elements of RHS. If an element of LHS can't be mapped to a unique element of
|
2011-12-12 12:36:15 +08:00
|
|
|
RHS for some reason (e.g. LHS is bigger than RHS) then it can also be mapped to the
|
|
|
|
special -1 output, indicating no mapping to RHS.
|
2011-12-12 06:15:18 +08:00
|
|
|
|
|
|
|
So the first step is to define the type of elements in each of these sets. In the
|
|
|
|
code below we will use column vectors in both LHS and RHS. However, in general,
|
|
|
|
they can each contain any type you like. LHS can even contain a different type
|
|
|
|
than RHS.
|
|
|
|
*/
|
|
|
|
|
|
|
|
typedef dlib::matrix<double,0,1> column_vector;
|
|
|
|
|
|
|
|
// This type represents a pair of LHS and RHS. That is, sample_type::first
|
|
|
|
// contains a left hand set and sample_type::second contains a right hand set.
|
|
|
|
typedef std::pair<std::vector<column_vector>, std::vector<column_vector> > sample_type;
|
|
|
|
|
|
|
|
// This type will contain the association information between LHS and RHS. That is,
|
|
|
|
// it will determine which elements of LHS map to which elements of RHS.
|
|
|
|
typedef std::vector<long> label_type;
|
|
|
|
|
|
|
|
// In this example, all our LHS and RHS elements will be 3-dimensional vectors.
|
|
|
|
const unsigned long num_dims = 3;
|
|
|
|
|
|
|
|
void make_data (
|
|
|
|
std::vector<sample_type>& samples,
|
|
|
|
std::vector<label_type>& labels
|
|
|
|
);
|
|
|
|
/*!
|
|
|
|
ensures
|
|
|
|
- This function creates a training dataset of 5 example associations.
|
|
|
|
- #samples.size() == 5
|
|
|
|
- #labels.size() == 5
|
|
|
|
- for all valid i:
|
|
|
|
- #samples[i].first == a left hand set
|
|
|
|
- #samples[i].second == a right hand set
|
|
|
|
- #labels[i] == a set of integers indicating how to map LHS to RHS. To be
|
|
|
|
precise:
|
|
|
|
- #samples[i].first.size() == #labels[i].size()
|
|
|
|
- for all valid j:
|
|
|
|
-1 <= #labels[i][j] < #samples[i].second.size()
|
|
|
|
(A value of -1 indicates that #samples[i].first[j] isn't associated with anything.
|
|
|
|
All other values indicate the associating element of #samples[i].second)
|
|
|
|
- All elements of #labels[i] which are not equal to -1 are unique. That is,
|
|
|
|
multiple elements of #samples[i].first can't associate to the same element
|
|
|
|
in #samples[i].second.
|
|
|
|
!*/
|
|
|
|
|
|
|
|
// ----------------------------------------------------------------------------------------
|
|
|
|
|
|
|
|
struct feature_extractor
|
|
|
|
{
|
|
|
|
/*!
|
|
|
|
Recall that our task is to learn the "goodness of assignment" function for
|
|
|
|
use with the Hungarian algorithm. The dlib tools assume this function
|
|
|
|
can be written as:
|
|
|
|
match_score(l,r) == dot(w, PSI(l,r))
|
|
|
|
where l is an element of LHS, r is an element of RHS, w is a parameter vector,
|
|
|
|
and PSI() is a user supplied feature extractor.
|
|
|
|
|
|
|
|
This feature_extractor is where we implement PSI(). How you implement this
|
|
|
|
is highly problem dependent.
|
|
|
|
!*/
|
|
|
|
|
|
|
|
// The type of feature vector returned from get_features(). This must be either
|
|
|
|
// a dlib::matrix or a sparse vector.
|
|
|
|
typedef column_vector feature_vector_type;
|
|
|
|
|
|
|
|
// The types of elements in the LHS and RHS sets
|
|
|
|
typedef column_vector lhs_element;
|
|
|
|
typedef column_vector rhs_element;
|
|
|
|
|
|
|
|
|
|
|
|
unsigned long num_features() const
|
|
|
|
{
|
|
|
|
// Return the dimensionality of feature vectors produced by get_features()
|
|
|
|
return num_dims + 1;
|
|
|
|
}
|
|
|
|
|
|
|
|
void get_features (
|
|
|
|
const lhs_element& left,
|
|
|
|
const rhs_element& right,
|
|
|
|
feature_vector_type& feats
|
|
|
|
) const
|
|
|
|
/*!
|
|
|
|
ensures
|
|
|
|
- #feats == PSI(left,right)
|
|
|
|
(i.e. This function computes a feature vector which, in some sense,
|
|
|
|
captures information useful for deciding if matching left to right
|
|
|
|
is "good").
|
|
|
|
!*/
|
|
|
|
{
|
|
|
|
// We will have:
|
|
|
|
// - feats(i) == std::pow(left(i) - right(i), 2.0)
|
|
|
|
// Except for the last element of feats which will be equal to 1 and
|
|
|
|
// therefore function as a bias term. Again, how you define this feature
|
|
|
|
// extractor is highly problem dependent.
|
|
|
|
feats = join_cols(squared(left - right), ones_matrix<double>(1,1));
|
|
|
|
}
|
|
|
|
|
|
|
|
};
|
|
|
|
|
|
|
|
// We need to define serialize() and deserialize() for our feature extractor if we want
|
|
|
|
// to be able to serialize and deserialize our learned models. In this case the
|
|
|
|
// implementation is empty since our feature_extractor doesn't have any state. But you
|
|
|
|
// might define more complex feature extractors which have state that needs to be saved.
|
|
|
|
void serialize (const feature_extractor& , std::ostream& ) {}
|
|
|
|
void deserialize (feature_extractor& , std::istream& ) {}
|
|
|
|
|
|
|
|
// ----------------------------------------------------------------------------------------
|
|
|
|
|
|
|
|
int main()
|
|
|
|
{
|
|
|
|
try
|
|
|
|
{
|
|
|
|
// Get a small bit of training data.
|
|
|
|
std::vector<sample_type> samples;
|
|
|
|
std::vector<label_type> labels;
|
|
|
|
make_data(samples, labels);
|
|
|
|
|
|
|
|
|
|
|
|
structural_assignment_trainer<feature_extractor> trainer;
|
|
|
|
// This is the common SVM C parameter. Larger values encourage the
|
|
|
|
// trainer to attempt to fit the data exactly but might overfit.
|
|
|
|
// In general, you determine this parameter by cross-validation.
|
|
|
|
trainer.set_c(10);
|
|
|
|
// This trainer can use multiple CPU cores to speed up the training.
|
|
|
|
// So set this to the number of available CPU cores.
|
|
|
|
trainer.set_num_threads(4);
|
|
|
|
|
|
|
|
// Do the training and save the results in assigner.
|
|
|
|
assignment_function<feature_extractor> assigner = trainer.train(samples, labels);
|
|
|
|
|
|
|
|
|
|
|
|
// Test the assigner on our data. The output will indicate that it makes the
|
|
|
|
// correct associations on all samples.
|
|
|
|
cout << "Test the learned assignment function: " << endl;
|
|
|
|
for (unsigned long i = 0; i < samples.size(); ++i)
|
|
|
|
{
|
|
|
|
// Predict the assignments for the LHS and RHS in samples[i].
|
|
|
|
std::vector<long> predicted_assignments = assigner(samples[i]);
|
|
|
|
cout << "true labels: " << trans(vector_to_matrix(labels[i]));
|
|
|
|
cout << "predicted labels: " << trans(vector_to_matrix(predicted_assignments)) << endl;
|
|
|
|
}
|
|
|
|
|
2011-12-12 12:36:15 +08:00
|
|
|
// We can also use this tool to compute the percentage of assignments predicted correctly.
|
2011-12-12 06:15:18 +08:00
|
|
|
cout << "training accuracy: " << test_assignment_function(assigner, samples, labels) << endl;
|
|
|
|
|
|
|
|
|
|
|
|
// Since testing on your training data is a really bad idea, we can also do 5-fold cross validation.
|
|
|
|
// Happily, this also indicates that all associations were made correctly.
|
|
|
|
randomize_samples(samples, labels);
|
|
|
|
cout << "cv accuracy: " << cross_validate_assignment_trainer(trainer, samples, labels, 5) << endl;
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
// Finally, the assigner can be serialized to disk just like most dlib objects.
|
|
|
|
ofstream fout("assigner.dat", ios::binary);
|
|
|
|
serialize(assigner, fout);
|
|
|
|
fout.close();
|
|
|
|
|
|
|
|
// recall from disk
|
|
|
|
ifstream fin("assigner.dat", ios::binary);
|
|
|
|
deserialize(assigner, fin);
|
|
|
|
}
|
|
|
|
catch (std::exception& e)
|
|
|
|
{
|
|
|
|
cout << "EXCEPTION THROWN" << endl;
|
|
|
|
cout << e.what() << endl;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
|
|
|
|
// ----------------------------------------------------------------------------------------
|
|
|
|
|
|
|
|
void make_data (
|
|
|
|
std::vector<sample_type>& samples,
|
|
|
|
std::vector<label_type>& labels
|
|
|
|
)
|
|
|
|
{
|
|
|
|
// Make four different vectors. We will use them to make example assignments.
|
|
|
|
column_vector A(num_dims), B(num_dims), C(num_dims), D(num_dims);
|
|
|
|
A = 1,0,0;
|
|
|
|
B = 0,1,0;
|
|
|
|
C = 0,0,1;
|
|
|
|
D = 0,1,1;
|
|
|
|
|
|
|
|
std::vector<column_vector> lhs;
|
|
|
|
std::vector<column_vector> rhs;
|
|
|
|
label_type mapping;
|
|
|
|
|
2011-12-12 06:29:47 +08:00
|
|
|
// In all the assignments to follow, we will only say an element of the LHS
|
|
|
|
// matches an element of the RHS if the two are equal. So A matches with A,
|
2011-12-12 06:15:18 +08:00
|
|
|
// B with B, etc. But never A with C, for example.
|
|
|
|
// ------------------------
|
|
|
|
|
|
|
|
lhs.resize(3);
|
|
|
|
lhs[0] = A;
|
|
|
|
lhs[1] = B;
|
|
|
|
lhs[2] = C;
|
|
|
|
|
|
|
|
rhs.resize(3);
|
|
|
|
rhs[0] = B;
|
|
|
|
rhs[1] = A;
|
|
|
|
rhs[2] = C;
|
|
|
|
|
|
|
|
mapping.resize(3);
|
|
|
|
mapping[0] = 1; // lhs[0] matches rhs[1]
|
|
|
|
mapping[1] = 0; // lhs[1] matches rhs[0]
|
|
|
|
mapping[2] = 2; // lhs[2] matches rhs[2]
|
|
|
|
|
|
|
|
samples.push_back(make_pair(lhs,rhs));
|
|
|
|
labels.push_back(mapping);
|
|
|
|
|
|
|
|
// ------------------------
|
|
|
|
|
|
|
|
lhs[0] = C;
|
|
|
|
lhs[1] = A;
|
|
|
|
lhs[2] = B;
|
|
|
|
|
|
|
|
rhs[0] = A;
|
|
|
|
rhs[1] = B;
|
|
|
|
rhs[2] = D;
|
|
|
|
|
|
|
|
mapping[0] = -1; // The -1 indicates that lhs[0] doesn't match anything in rhs.
|
|
|
|
mapping[1] = 0; // lhs[1] matches rhs[0]
|
|
|
|
mapping[2] = 1; // lhs[2] matches rhs[1]
|
|
|
|
|
|
|
|
samples.push_back(make_pair(lhs,rhs));
|
|
|
|
labels.push_back(mapping);
|
|
|
|
|
|
|
|
// ------------------------
|
|
|
|
|
|
|
|
lhs[0] = A;
|
|
|
|
lhs[1] = B;
|
|
|
|
lhs[2] = C;
|
|
|
|
|
|
|
|
rhs.resize(4);
|
|
|
|
rhs[0] = C;
|
|
|
|
rhs[1] = B;
|
|
|
|
rhs[2] = A;
|
|
|
|
rhs[3] = D;
|
|
|
|
|
|
|
|
mapping[0] = 2;
|
|
|
|
mapping[1] = 1;
|
|
|
|
mapping[2] = 0;
|
|
|
|
|
|
|
|
samples.push_back(make_pair(lhs,rhs));
|
|
|
|
labels.push_back(mapping);
|
|
|
|
|
|
|
|
// ------------------------
|
|
|
|
|
|
|
|
lhs.resize(2);
|
|
|
|
lhs[0] = B;
|
|
|
|
lhs[1] = C;
|
|
|
|
|
|
|
|
rhs.resize(3);
|
|
|
|
rhs[0] = C;
|
|
|
|
rhs[1] = A;
|
|
|
|
rhs[2] = D;
|
|
|
|
|
|
|
|
mapping.resize(2);
|
|
|
|
mapping[0] = -1;
|
|
|
|
mapping[1] = 0;
|
|
|
|
|
|
|
|
samples.push_back(make_pair(lhs,rhs));
|
|
|
|
labels.push_back(mapping);
|
|
|
|
|
|
|
|
// ------------------------
|
|
|
|
|
|
|
|
lhs.resize(3);
|
|
|
|
lhs[0] = D;
|
|
|
|
lhs[1] = B;
|
|
|
|
lhs[2] = C;
|
|
|
|
|
|
|
|
// rhs will be empty. So none of the items in lhs can match anything.
|
|
|
|
rhs.resize(0);
|
|
|
|
|
|
|
|
mapping.resize(3);
|
|
|
|
mapping[0] = -1;
|
|
|
|
mapping[1] = -1;
|
|
|
|
mapping[2] = -1;
|
|
|
|
|
|
|
|
samples.push_back(make_pair(lhs,rhs));
|
|
|
|
labels.push_back(mapping);
|
|
|
|
|
|
|
|
}
|
|
|
|
|