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a3e846685d
See contained diff. The upsampling is important for Voice Messages, but is being done here because it's easier to add all the tests at once. This also introduces a new Object utility - that will be tested on its own commit.
295 lines
11 KiB
TypeScript
295 lines
11 KiB
TypeScript
/*
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Copyright 2021 The Matrix.org Foundation C.I.C.
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Licensed under the Apache License, Version 2.0 (the "License");
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you may not use this file except in compliance with the License.
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You may obtain a copy of the License at
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http://www.apache.org/licenses/LICENSE-2.0
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Unless required by applicable law or agreed to in writing, software
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distributed under the License is distributed on an "AS IS" BASIS,
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WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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See the License for the specific language governing permissions and
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limitations under the License.
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*/
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import {
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arrayDiff,
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arrayFastClone,
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arrayFastResample,
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arrayHasDiff,
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arrayHasOrderChange,
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arrayMerge,
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arraySeed,
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arrayUnion,
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ArrayUtil,
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GroupedArray,
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} from "../src/utils/arrays";
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import {objectFromEntries} from "../src/utils/objects";
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function expectSample(i: number, input: number[], expected: number[]) {
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console.log(`Resample case index: ${i}`); // for debugging test failures
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const result = arrayFastResample(input, expected.length);
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expect(result).toBeDefined();
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expect(result).toHaveLength(expected.length);
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expect(result).toEqual(expected);
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}
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describe('arrays', () => {
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describe('arrayFastResample', () => {
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it('should downsample', () => {
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[
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{input: [1, 2, 3, 4, 5], output: [1, 4]}, // Odd -> Even
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{input: [1, 2, 3, 4, 5], output: [1, 3, 5]}, // Odd -> Odd
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{input: [1, 2, 3, 4], output: [1, 2, 3]}, // Even -> Odd
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{input: [1, 2, 3, 4], output: [1, 3]}, // Even -> Even
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].forEach((c, i) => expectSample(i, c.input, c.output));
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});
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it('should upsample', () => {
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[
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{input: [1, 2, 3], output: [1, 1, 2, 2, 3, 3]}, // Odd -> Even
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{input: [1, 2, 3], output: [1, 1, 2, 2, 3]}, // Odd -> Odd
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{input: [1, 2], output: [1, 1, 1, 2, 2]}, // Even -> Odd
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{input: [1, 2], output: [1, 1, 1, 2, 2, 2]}, // Even -> Even
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].forEach((c, i) => expectSample(i, c.input, c.output));
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});
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it('should maintain sample', () => {
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[
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{input: [1, 2, 3], output: [1, 2, 3]}, // Odd
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{input: [1, 2], output: [1, 2]}, // Even
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].forEach((c, i) => expectSample(i, c.input, c.output));
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});
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});
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describe('arraySeed', () => {
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it('should create an array of given length', () => {
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const val = 1;
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const output = [val, val, val];
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const result = arraySeed(val, output.length);
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expect(result).toBeDefined();
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expect(result).toHaveLength(output.length);
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expect(result).toEqual(output);
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});
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it('should maintain pointers', () => {
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const val = {}; // this works because `{} !== {}`, which is what toEqual checks
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const output = [val, val, val];
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const result = arraySeed(val, output.length);
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expect(result).toBeDefined();
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expect(result).toHaveLength(output.length);
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expect(result).toEqual(output);
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});
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});
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describe('arrayFastClone', () => {
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it('should break pointer reference on source array', () => {
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const val = {}; // we'll test to make sure the values maintain pointers too
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const input = [val, val, val];
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const result = arrayFastClone(input);
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expect(result).toBeDefined();
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expect(result).toHaveLength(input.length);
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expect(result).toEqual(input); // we want the array contents to match...
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expect(result).not.toBe(input); // ... but be a different reference
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});
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});
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describe('arrayHasOrderChange', () => {
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it('should flag true on B ordering difference', () => {
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const a = [1, 2, 3];
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const b = [3, 2, 1];
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const result = arrayHasOrderChange(a, b);
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expect(result).toBe(true);
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});
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it('should flag false on no ordering difference', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 3];
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const result = arrayHasOrderChange(a, b);
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expect(result).toBe(false);
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});
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it('should flag true on A length > B length', () => {
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const a = [1, 2, 3, 4];
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const b = [1, 2, 3];
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const result = arrayHasOrderChange(a, b);
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expect(result).toBe(true);
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});
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it('should flag true on A length < B length', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 3, 4];
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const result = arrayHasOrderChange(a, b);
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expect(result).toBe(true);
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});
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});
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describe('arrayHasDiff', () => {
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it('should flag true on A length > B length', () => {
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const a = [1, 2, 3, 4];
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const b = [1, 2, 3];
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const result = arrayHasDiff(a, b);
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expect(result).toBe(true);
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});
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it('should flag true on A length < B length', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 3, 4];
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const result = arrayHasDiff(a, b);
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expect(result).toBe(true);
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});
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it('should flag true on element differences', () => {
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const a = [1, 2, 3];
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const b = [4, 5, 6];
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const result = arrayHasDiff(a, b);
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expect(result).toBe(true);
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});
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it('should flag false if same but order different', () => {
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const a = [1, 2, 3];
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const b = [3, 1, 2];
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const result = arrayHasDiff(a, b);
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expect(result).toBe(false);
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});
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it('should flag false if same', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 3];
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const result = arrayHasDiff(a, b);
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expect(result).toBe(false);
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});
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});
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describe('arrayDiff', () => {
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it('should see added from A->B', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 3, 4];
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const result = arrayDiff(a, b);
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expect(result).toBeDefined();
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expect(result.added).toBeDefined();
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expect(result.removed).toBeDefined();
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expect(result.added).toHaveLength(1);
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expect(result.removed).toHaveLength(0);
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expect(result.added).toEqual([4]);
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});
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it('should see removed from A->B', () => {
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const a = [1, 2, 3];
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const b = [1, 2];
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const result = arrayDiff(a, b);
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expect(result).toBeDefined();
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expect(result.added).toBeDefined();
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expect(result.removed).toBeDefined();
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expect(result.added).toHaveLength(0);
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expect(result.removed).toHaveLength(1);
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expect(result.removed).toEqual([3]);
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});
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it('should see added and removed in the same set', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 4]; // note diff
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const result = arrayDiff(a, b);
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expect(result).toBeDefined();
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expect(result.added).toBeDefined();
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expect(result.removed).toBeDefined();
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expect(result.added).toHaveLength(1);
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expect(result.removed).toHaveLength(1);
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expect(result.added).toEqual([4]);
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expect(result.removed).toEqual([3]);
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});
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});
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describe('arrayUnion', () => {
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it('should return a union', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 4]; // note diff
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const result = arrayUnion(a, b);
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expect(result).toBeDefined();
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expect(result).toHaveLength(2);
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expect(result).toEqual([1, 2]);
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});
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it('should return an empty array on no matches', () => {
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const a = [1, 2, 3];
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const b = [4, 5, 6];
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const result = arrayUnion(a, b);
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expect(result).toBeDefined();
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expect(result).toHaveLength(0);
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});
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});
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describe('arrayMerge', () => {
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it('should merge 3 arrays with deduplication', () => {
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const a = [1, 2, 3];
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const b = [1, 2, 4, 5]; // note missing 3
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const c = [6, 7, 8, 9];
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const result = arrayMerge(a, b, c);
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expect(result).toBeDefined();
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expect(result).toHaveLength(9);
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expect(result).toEqual([1, 2, 3, 4, 5, 6, 7, 8, 9]);
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});
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it('should deduplicate a single array', () => {
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// dev note: this is technically an edge case, but it is described behaviour if the
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// function is only provided one function (it'll merge the array against itself)
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const a = [1, 1, 2, 2, 3, 3];
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const result = arrayMerge(a);
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expect(result).toBeDefined();
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expect(result).toHaveLength(3);
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expect(result).toEqual([1, 2, 3]);
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});
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});
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describe('ArrayUtil', () => {
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it('should maintain the pointer to the given array', () => {
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const input = [1, 2, 3];
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const result = new ArrayUtil(input);
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expect(result.value).toBe(input);
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});
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it('should group appropriately', () => {
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const input = [['a', 1], ['b', 2], ['c', 3], ['a', 4], ['a', 5], ['b', 6]];
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const output = {
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'a': [['a', 1], ['a', 4], ['a', 5]],
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'b': [['b', 2], ['b', 6]],
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'c': [['c', 3]],
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};
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const result = new ArrayUtil(input).groupBy(p => p[0]);
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expect(result).toBeDefined();
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expect(result.value).toBeDefined();
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const asObject = objectFromEntries(result.value.entries());
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expect(asObject).toMatchObject(output);
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});
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});
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describe('GroupedArray', () => {
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it('should maintain the pointer to the given map', () => {
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const input = new Map([
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['a', [1, 2, 3]],
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['b', [7, 8, 9]],
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['c', [4, 5, 6]],
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]);
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const result = new GroupedArray(input);
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expect(result.value).toBe(input);
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});
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it('should ordering by the provided key order', () => {
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const input = new Map([
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['a', [1, 2, 3]],
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['b', [7, 8, 9]], // note counting diff
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['c', [4, 5, 6]],
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]);
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const output = [4, 5, 6, 1, 2, 3, 7, 8, 9];
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const keyOrder = ['c', 'a', 'b']; // note weird order to cause the `output` to be strange
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const result = new GroupedArray(input).orderBy(keyOrder);
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expect(result).toBeDefined();
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expect(result.value).toBeDefined();
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expect(result.value).toEqual(output);
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});
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});
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});
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