mlat: fixed horrible bug in the solver. also noticed that [0,0,0] cannot contribute meaningful angular data, and so you still really want four stations on receive. there's still a bug in the solver somewhere that results in positions east of here not solving correctly.
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@ -3,21 +3,26 @@ import mlat
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import numpy
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#here's some test data to validate the algorithm
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teststations = [[37.76225, -122.44254, 100], [37.409044, -122.077748, 100], [37.585085, -121.986395, 100]]
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teststations = [[37.76225, -122.44254, 100], [37.409044, -122.077748, 100], [37.63816,-122.378082, 100], [37.701207,-122.309418, 100]]
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testalt = 8000
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testplane = numpy.array(mlat.llh2ecef([37.617175,-122.380843, testalt]))
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testplane = numpy.array(mlat.llh2ecef([37.617175,-122.400843, testalt]))
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testme = mlat.llh2geoid(teststations[0])
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teststamps = [10,
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10 + numpy.linalg.norm(testplane-numpy.array(mlat.llh2geoid(teststations[1]))) / mlat.c,
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10 + numpy.linalg.norm(testplane-numpy.array(mlat.llh2geoid(teststations[2]))) / mlat.c,
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10 + numpy.linalg.norm(testplane-numpy.array(mlat.llh2geoid(teststations[3]))) / mlat.c,
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]
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print teststamps
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replies = []
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for i in range(0, len(teststations)):
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replies.append((teststations[i], teststamps[i]))
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ans = mlat.mlat(replies, testalt)
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error = numpy.linalg.norm(numpy.array(mlat.llh2ecef(ans))-numpy.array(testplane))
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range = numpy.linalg.norm(mlat.llh2geoid(ans)-numpy.array(mlat.llh2geoid(teststations[0])))
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range = numpy.linalg.norm(mlat.llh2geoid(ans)-numpy.array(testme))
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print testplane-testme
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print ans
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print "Error: %.2fm" % (error)
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print "Range: %.2fkm (from first station in list)" % (range/1000)
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@ -151,7 +151,8 @@ c = 299792458 / 1.0003 #modified for refractive index of air, why not
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#we use limit as a goal to stop solving when we get "close enough" (error magnitude in meters for that iteration)
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#basically 20 meters is way less than the anticipated error of the system so it doesn't make sense to continue
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#it's possible this could fail in situations where the solution converges slowly
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def mlat_iter(rel_stations, prange_obs, xguess = [0,0,0], limit = 20, maxrounds = 50):
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#TODO: this fails to converge for some seriously advantageous geometry
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def mlat_iter(rel_stations, prange_obs, xguess = [0,0,0], limit = 20, maxrounds = 100):
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xerr = [1e9, 1e9, 1e9]
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rounds = 0
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while numpy.linalg.norm(xerr) > limit:
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@ -161,11 +162,12 @@ def mlat_iter(rel_stations, prange_obs, xguess = [0,0,0], limit = 20, maxrounds
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dphat = prange_obs - prange_est
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H = []
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for row in range(0,len(rel_stations)):
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H.append((numpy.array(-rel_stations[row,:])-xguess) / prange_est[row])
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H.append((numpy.array(-rel_stations[row,:])+xguess) / prange_est[row])
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H = numpy.array(H)
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#now we have H, the Jacobian, and can solve for residual error
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xerr = numpy.linalg.lstsq(H, dphat)[0].flatten() #let's not get crazy here
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xerr = numpy.linalg.lstsq(H, dphat)[0].flatten()
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xguess += xerr
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print xguess, xerr
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rounds += 1
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if rounds > maxrounds:
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raise Exception("Failed to converge!")
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@ -207,13 +209,17 @@ def mlat(replies, altitude):
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prange_obs.append([c * stamp])
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#so here we calc the estimated pseudorange to the center of the earth, using station[0] as a reference point for the geoid
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#in other words, we say "if the aircraft were directly overhead of station[0], this is the prange to the center of the earth"
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#this is a necessary approximation since we don't know the location of the aircraft yet
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#if the dang earth were actually round this wouldn't be an issue
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prange_obs.append( [numpy.linalg.norm(llh2ecef((me_llh[0], me_llh[1], altitude)))] ) #use ECEF not geoid since alt is MSL not GPS
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#prange_obs.append( [numpy.linalg.norm(testplane)]) #test for error
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prange_obs = numpy.array(prange_obs)
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#xguess = llh2ecef([37.617175,-122.400843, 8000])-numpy.array(me)
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xguess = [0,0,0]
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#xguess = numpy.array(llh2ecef([stations[2][0], stations[2][1], altitude])) - numpy.array(me)
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xyzpos = mlat_iter(rel_stations, prange_obs)
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xyzpos = mlat_iter(rel_stations, prange_obs, xguess)
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llhpos = ecef2llh(xyzpos+me)
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#now, we could return llhpos right now and be done with it.
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@ -227,7 +233,7 @@ def mlat(replies, altitude):
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llhpos = ecef2llh(xyzpos_corr+me)
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#and now, what the hell, let's try to get dilution of precision data
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#avec is the vector of relative ranges to the aircraft from each of the stations
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#avec is the unit vector of relative ranges to the aircraft from each of the stations
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# for i in range(len(avec)):
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# avec[i] = numpy.array(avec[i]) / numpy.linalg.norm(numpy.array(avec[i]))
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# numpy.append(avec, [[-1],[-1],[-1],[-1]], 1) #must be # of stations
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